This library is built in the open.
If you spot an error, have a suggestion, or just want to say hello — we’d love to hear from you.

Divided by 417;12. "Trinavagunastihatat" means 3, 9, 60, and 8 the divisor 16393. Divided by that. "Bhaganadih" means the revolution at the beginning. "Himamśuh" means the Moon. The Moon starting from the cycle becomes [this value]. The word "va" or is for another method here. When done in this way, the Moon is obtained. What is the specialty? He says: "Navayamatanaih kalarahitah." The Moon, which has been previously calculated, should be corrected by the minutes derived from the day-count.
Manual: Having calculated the desired day-count, multiply by 600. Then, it should be increased by 417;12. Then, it should be divided by 16393. The obtained value is the Moon starting from the revolutions. Multiply the remainder of the revolutions by 12, and below that, multiply the 12 ghatikas by 12. When divided by 60, two values, 24 ghatikas, are obtained; add them to the top. Then, when divided by 16393, the signs are obtained. Multiply the remainder of the signs by 30, and below that, put the 24 ghatikas. Multiply those also by 30. When divided by 60, 12 are obtained; add them to the top. The remainder is as before. Its manual is: for the planets Mars, etc., the signs, degrees, and minutes should be sought like the Sun. Then, again, divide the day-count by 4929. The obtained result in minutes, etc., should be subtracted from the previously calculated Moon, and the midnight mean Moon will be obtained. In this way—
Example: Thus, the day-count is 72715. This, multiplied by 600, is 43628000. Adding 41712 to this results in 4362841712. When divided by 16393, the Moon starting with signs is obtained as 5;17;51;15. (This calculation done separately is subject to error; the pure result here is 5;17;51;16, according to the editor). Then, again, the day-count 72715 divided by 4929 gives the result in minutes: 14;45. (Then the mean Moon becomes 5;17;36;30, by separate calculation). Subtracting this because it is not previously obtained, the mean Moon becomes 5;17;31. (Here, any subtraction is unnecessary because the result in minutes, 14;45, is from the first obtained Moon...)
2