We, Chunfeng and others, respectfully follow the dense ratio, resulting in an area of 10 mu and 87/88 of 205 bu.

The procedure says: Multiply half the circumference by half the diameter to obtain the area in bu.

Note: Half the circumference is the width.
Half the diameter is the length, hence.

Multiplying width by length gives the area. Suppose the circular diameter is 2 chi feet. One side of the six-arc referring to the side of a regular hexagon inscribed in a circle inscribed in the circle is equal to the radius. Make...

...the diameter ratio 1, and the arc-circumference ratio 3. Also, to make a circle, multiply one side of the six-arc by the radius of the one-arc and multiply by 3, then divide by 1...

...to obtain the power area of the six-arc. If one cuts it further, next multiply one side of the twelve-arc by the radius of the one-arc and multiply by 6, then divide by 1...

...to obtain the power of the twelve-arc. Cut it ever finer, and the loss becomes ever less. If one cuts and cuts again until it cannot be cut further, it will coincide with the circle's...

...circumference, forming a single body with no loss. Outside the arc face, there is still a remaining diameter. If one multiplies the face by the diameter, the power exceeds the arc's surface. If the arc...

...is fine enough to coincide with the circle, then the surface has no remaining diameter. If the surface has no remaining diameter, the power does not extend outward. Multiply half the circumference by the radius...

...to obtain the circular power. This is because the circumference and diameter are based on the ring of six arcs. To infer the ratio of the circle, the circumference of 3 follows its six arcs.